Question

two resistors of 10 ohm and 15 ohm are connected in series to a battery of 6 volt how can the value of current passing through them the compare answer is 1 ratio 1

Answer 1

Answer:

Given that - R1 = 10 ohm

R2 = 15 ohm

V = 6 volt

Though R1 & R2 are connected in series ..so by series conbination ,

R net = R1 + R2 = 10 + 15 = 25 ohm

By ohms law , V = I X R

I = V / R = 6 / 25 = 0.24 Ampere

Though R1 and R2 are in series so value of current will flow same in all the resistors...

so ratio of current = I / I = 0.24 / 0.24 = 1 : 1

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