Question

two resistors of 10 ohm and 15 ohm are connected in series to a battery of 6 volt how can the value of current passing through them be compared

Answer 1

Find the equivalent resistance

Given :

10 Ω and 15 Ω are in series.

Let the equivalent resistance be R.

This means that R = 10 Ω + 15 Ω

                              = 25 Ω

Find the current

By Ohm's Law :

V = I R

Given :

V = 6 v

R = 25 Ω [ as calculated above ]

So :

V = I R

==> 6 v = I × 25 Ω

==> I = 25 Ω / 6 v

==> I = 4.1666 A

$\boxed{\bf{ANSWER}}$

The current flowing in the circuit is 4.167 A

Hope it helps !

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