Question

Two resistors of 5 Ω and 10 Ω are connected in series to a 45 V battery. What is the current flowing through the circuit

Answer 1

Answer:3 A

Explanation:

Equivalent resistance equal to 5 + 10=15 ohm

I=V/R=45/15=3 A

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Answer 2

TOTAL RESISTANCE=(5+10)Ω

                                  =15Ω

P.D.(BATTERY)=45 V

CURRENT IN THE CIRCUIT= POTENTIAL DIFFERENCE(V)/RESISTANCE(R)

                                              =45/15

                                              =3 A

AAYA SAMAJ.