Two resistors of 6ohm and 18ohm are connected in parallel and a battery of 3V is connected across them. Find the equivalent resistance of a circuit, the total current and the current through each resistor.
Answers
Answered by
1
Answer:
The total series resistance R= R1 +R2 +Rn and so the total resistance is 18+6 ohms.
Note: There may be an additional internal resistance of the battery, assumed to be zero in this case)
Answered by
1
Answer:
Given:
R₁=6Ω
R₂=18Ω
V = 3V
I₁=V/R₁
I₁=3V/6Ω
I₁= 0.5A
I₂=V/R₂
I₂=3V/18Ω
I₂=1/6A
Total I = I₁ + I₂
Total I = 0.5A + 1/6A
Total I = 0.6666A
Total I = 0.67A
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