Two resistors of 6ohm and 9ohm are connected in series to a 120v source. Find the power consumed by 6ohm resistor.
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Ans:- If the resistors are connected in series then their total resistance will be R= R1+R2
R= 6+9=15
Now,in accordance with ohm's law
V=IR
120=I*15
I = 8 A
Now, we know that power = I²R
So,
we have. 8*8*6
This will give give you 384 W Ans.
Explanation:
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