Physics, asked by rithurithz, 7 months ago

Two resistors of resistances R1 = (100 ± 1) Ω and R2 = (200 ± 2) Ω are connected in parallel. The resistance of the parallel combination is? ​

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Answered by sahuji9761
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Two resistors of resistances R1 = (100 ± 3) Ω and R2 = (200 ± 4) Ω are connected in parallel. The equivalent resistance of the parallel ...

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Here, R1 (100 ± 3) Ω; R2 = (200 ± 4) Ω The equivalent resistance in parallel combination is 1/R1 = 1/R1 + 1/R2, 1/Rp = 1/100 + 1/200 = 3/200, Rp =

Answered by palakgupta2395
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