Question

Two resistors of resistances R1 = 150 ± 2 Ohm and R2 = 220 ± 6 Ohm are connected in parallel combination.

Calculate the equivalent resistance.

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Answer 1

Answer:

given that R1 = 150 +- 2 ohm

R2 = 220+-6

Req in case of parallel combination

1/Req = 1/150 + 1/220

1/Req = 37/3300

Req = 3300/37

Req = 89.2 approx

now we are also given some errors , we will add errors

2+6= 8

final answer will be :

89.2 +- 8

Answer 2

Answer:

Two resistors,R1 and R2 are connected in parallel .

We know,

[tex]1 \frac{re \: = 1 \frac{r1 + 1 \frac{r2 \\ then \: re = r1r2 \frac{r1 + r2 \\ = 50 \times 100 \frac{50 + 100 = 5000 \frac{150 = 100 \frac{3 \\ now \: parallel \: parallel \:connection \: error \\ r2 \frac{1(db) + r2 \frac{2(r1 + r2) {2 \\ 50 {2(3) + 100 {2() \frac{150 {2 \\ 7500 + 20000 \frac{150 \times 150 \\ = 11 \frac{9 \\ relative \: error = (11 \frac{9) \frac{(100 \frac{3) = 0.03666