Two resistors with resistance 5ohm and 10ohm respectively are to be connected to a battery of 6V so as to obtain:calculate the strengthof the total current in the circuit in the two cases
Answers
Two resistors with resistances 5 ohm and 10 ohm are to be connected to a battery of emf 6 V so as to obtain :
1) minimum current.
2) maximum current.
A) How will you connect the resistance in each case .
B) Calculate the strength of total current in the circuit in the 2 cases.
Ask for details Follow Report by Anagha 29.05.2014
Answers
prmkulk1978
prmkulk1978 Ace
Dear Student,
Given:
R1=5Ω
R2=10Ω
EMF=6V
A)
To get minimum current, the two resistors should be connected in series.
To get maximum current, we should connect the resistance in parallel
B)To calculate strength of total current in each case:
1) To get minimum current, the two resistors should be connected in series.
Effective resistance for series connection: R= R1+R2
R=5+10
R=15Ω
By Ohm's law, we have V=IR
so, I=V/R
⇒6/15⇒0.4A
I=0.4A
2) To get maximum current, we should connect the resistance in parallel.
Effective resistance for parallel connection: 1/R=1/R1+1/R2
1/R=R1+R2/R1R2
∴R=R1R2/R1+R2
⇒5x10/5+10
⇒50/15⇒10/3Ω
By Ohm's law, we have V=IR
so, I=V/R
⇒(6/10)x3⇒1.8A
I=1.8A
Hope its clear
