Two resistors with resistance of 10 ohm and 15 ohm are connected in parallel to a battery of 12 volt find the current drawn from the battery
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Electricity
Here
R = 10 ohm
R'= 15 ohm
R and R' are connected parallely.
So the equivalent resistance R" = [1/{(1/10)+(1/15)}] ohm
= 6 ohm
and potential difference of the battery, V = 12 v
Let the current that flows throw the wire be I A
We know that
V = IR"
=> 12 = I×6
=> I = 2 A
So the current that flows throw the circuit is 2ampere .
That's it
Hope it helped
^_^
Here
R = 10 ohm
R'= 15 ohm
R and R' are connected parallely.
So the equivalent resistance R" = [1/{(1/10)+(1/15)}] ohm
= 6 ohm
and potential difference of the battery, V = 12 v
Let the current that flows throw the wire be I A
We know that
V = IR"
=> 12 = I×6
=> I = 2 A
So the current that flows throw the circuit is 2ampere .
That's it
Hope it helped
^_^
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