two right circular cones have equal radii if there slant height in ratio 4:3 then find there ratio of their curved surface areas
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Here is your solution ↓↓↓
Given that :-
Radii are equal .
Let radii be r and r respectively .
Ratio of slant height = 4:3
Let ratio constant be x .
L1 = 4x
L2 = 3x
Now ,
Curved surface area of first cone = pie * r * L1
= pie * r * 4x
Curved surface area of second cone = pie * r * L2
= pie * r * 3x
Ratio of CSA ( 1 ) and CSA ( 2 )
= pie * r * 4x / pie * r * 3x
= 4x / 3x
= 4/ 3
= 4 : 3
So , required ratio is 4 : 3
^_^
Here is your solution ↓↓↓
Given that :-
Radii are equal .
Let radii be r and r respectively .
Ratio of slant height = 4:3
Let ratio constant be x .
L1 = 4x
L2 = 3x
Now ,
Curved surface area of first cone = pie * r * L1
= pie * r * 4x
Curved surface area of second cone = pie * r * L2
= pie * r * 3x
Ratio of CSA ( 1 ) and CSA ( 2 )
= pie * r * 4x / pie * r * 3x
= 4x / 3x
= 4/ 3
= 4 : 3
So , required ratio is 4 : 3
^_^
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