Question

Two rings each of mass M and radius R, are placed with common centre such that their planes are mutually perpendicular. The moment of inertia of the system about an axis through the centre and perpendicular to plane of one of the ring is

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Answer 1

Answer:

3/2 mr² is your answer

Explanation:

Moment of Inertia of two rings system is sum of moment of inertia of individual rings.

Moment of inertia of the ring where axis is perpendicular to the plane of the ring = MR

2

Moment of inertia of the ring where axis is in the plane of the ring: I

1

=MR

2

Moment of inertia of the 2nd ring about axis passing through the center of the 1st ring and perpendicular to the plane of the 1st ring I

2

=

2

MR

2

where the the factor of

2

1

is due to perpendicular axis theorem.

Moment of inertia of the systemI=I

1

+I

2

=MR

2

+

2

MR

2

=

2

3

MR

2