Question

Two roads of width 3m run perpendicular to each other in the middle of a field. The field is of length 100m and breadth 80 m. The roads are laid at a cost 11 per m^2 and the remaining garden is levelled at ₹ 5 m^2. Find the total amount required.​

Answer 1

The total amount required is Rs. 43,186.

Step-by-step explanation:

• In the attached figure ABCD is rectangular field with 100m length and 80m breadth.
• Area of the field = 100 × 80 = 8000 $m^{2}$
• width of the road is 3m.
• Area of the road = (100 ×3) + (80 × 3 ) - (3 × 3)
•                           = 300 + 240 - 9 = 531  $m^{2}$

∴ Area of the garden = Area of the field - Area of the road

                                          = 8000  -  531 = 7469  $m^{2}$

• ∵cost of road per  $m^{2}$ = 11  Rs.
• ∴total cost of road = 11 × 531 = 5841 Rs.
• ∵ cost of garden levelling per  $m^{2}$ = 5  Rs.

∴total cost of garden levelling = 5 × 7469 = 37,345 Rs.

∴Total amount required = 5841 + 37,345 = 43,186  Rs.

Answer 2

Answer:

43186 sahi hi bhai

Mara yak saal hai .

-9+5