Two rods A and B of the same weight 10 kg and equal length 5m have different cross section area 20 cm
and 60 cm- respectively. They are beld vertically on the surface of sand. The ratio of pressure applied by A
to pressure applied by B on the sand is:
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Answered by
0
Answer:
sorry dude dont know
Explanation:
lol
Answered by
2
WE KNOW,
PRESSURE IS INVERSELY PROPORTIONAL TO CROSS SECTIONAL AREA
THEN,
PRESSURE APPLIED BY A = F/20
PRESSURE APPLIED BY B = F/60
THEIR RATIOS = (F/20) ÷ (F/60)
= 60/20
= 3:1
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