Question

What is the current (I) in the circuit? (A) 1.5 A (B) 2.5 A (C) 3.5 A (D) 4.5 A

Answer 1

Answer:

A

Explanation:

resistors on left side and downward side of triangale are in parallel connection

After that left and down side are in series with each other which is in parallel connection with right side

Answer 2

Given: circuit diagram

To Find: current (I) passing through the circuit

Solution:

According to the given circuit,

Consider the circuit ΔABC,

AB - 1 resistor =R₁ = 2ohms

AC and BC have 2 resistors connected in parallel each.

For AC and BC, the equivalent resistance of each are as follows:-

for resistors connected in parallel the equivalent resistance

= 1/R₁ + 1/R₂

=1/2 + 1/2

=2/2 = 1 ohm

Similarly, both AC and BC have an equivalent resistance of 1 ohm.

AB resistance (given) = 2 ohm -according to the circuit, it is parallel to the battery and also to AC and BC resistors which are in series to each other.

Resistance in series = AC and BC

                                 = R₁ + R₂

                                 = 1 + 1

                                 = 2 ohms

Now AC, BC resistance = 2 is parallel to 2ohm AB parallel to battery.

total equivalent resistance(R)  = 1/2 + 1/2

                                                   = 2/2 = 1 ohm

For current, formula used

V = IR ( V = voltage)⇒ ohms law

I = V/R

I = 1.5/1

I = 1.5Amperes / 1.5A