Question

Two rods of equal lengths (l) and equal mass m are kept along x and y axis respectively such that their centre of mass lie at origin. The moment of inertia about a line y=x, is
(1) ml²/3
(2) ml²/4
(3) ml²/12
(4) ml²/6​

Answer 1

Answer:

(1). ml²/3

Explanation:

M.O.I. rod lying on the x axis is

ml²sin²45/3

MOI rod lying on the y axis is

ml²cos²45/3

So,

MOI =ml²/6+ml²/6

=ml²/3

Answer 2

Answer:

Answer:

(1). ml²/3

Explanation:

M.O.I. rod lying on the x axis is

ml²sin²45/3

MOI rod lying on the y axis is

ml²cos²45/3

So,

MOI =ml²/6+ml²/6

=ml²/3

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@Harshit mangal