Two ropes, one 8 metres long and the other 12 metres long are to be cut into pieces of the same length. What will the maximum possible length of each piece be?
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Answer:
Therefore, maximum possible length of each pieces will be 4m.
Step-by-step explanation:
HCF of both the numbers will be the possible maximum length of the rope
So, we have to find the HCF of 8 and 12
to find the HCF of the numbers first we have to factorize the numbers
8 = 2 × 2 × 2
12 = 2 × 2 × 3
HCF(8, 12) = 2 × 2 = 4
Therefore, maximum possible length of each pieces will be 4m.
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two ropes . one 8 metres long and the other 12 metres long are to be cut into pieces of the same length. what will the maximum possible length of each piece be ?
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