two runners cover the same distance at the rates of the 10 km/hr and 12 km/hr respectively. Find the distance travelled when one takes 16 minutes longer than the other
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47
solution:-
Given :- speed s = distance(d)/time(t)
Since distance d is the same d = st
At 12 km/h, takes shorter time t
At 10 km/h, takes longer time (t + 16/60) =( t+4/15)
12(t) = (t + 4/15)10
=> 12t = 10t + 40/15
=> 12t-10t = 8/3
=>t = 4/3
D = st
=> 12×3/4 = 3×3 = 9km
■I HOPE ITS HELP■
Given :- speed s = distance(d)/time(t)
Since distance d is the same d = st
At 12 km/h, takes shorter time t
At 10 km/h, takes longer time (t + 16/60) =( t+4/15)
12(t) = (t + 4/15)10
=> 12t = 10t + 40/15
=> 12t-10t = 8/3
=>t = 4/3
D = st
=> 12×3/4 = 3×3 = 9km
■I HOPE ITS HELP■
Anonymous:
according to physics, s is distance not speed sir
here s is speed (s) simply
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5
Answer 9 km
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