Physics, asked by shipradrishti17, 1 year ago

Two satellites s and s' revolve around the earth at distance 3R and 12R from the Centre of the earth. The periods of revolution of s and s' are in ratio of

Answers

Answered by srushtimeshram
1

Explanation:

given that,

s and s' satellite revolving around the earth

therefore,radius of s satellite= 3R

and radius of s' satellite= 12R

we know that,

(T1/T2)^2 = (r1/r2)^3

(T1/T2)^2 = ( 3R /12R)

(T1/T2)^2=(1R/4R)

therefore, taking square root both the sides

(T1/T2) = 1/2

therefore, T1:T2 = 1:2

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