Two satellites s1 and s2 revolve around a planet in coplanar circular orbits in the opposite sense. The periods of revolutions are t and t respectively. Find the angular speed of s2 as observed by an astronaut in s1, when they are closest to each other.
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Hello dear, let's solve this,
Angular speed of satelite s2 w.r.t. s1 when they are closest to each other is given by,
w = |v1-v2| / |r1-r2|
But for planetary motion,
v1 = 2πr1/T1
v2 = 2πr2/T2
w = 2π× |(r1/T1 - r2/T2 ) ÷ (r1-r2)|
w = 2π× |(r1T2 - r2T1)/T1T2| ÷ |r1-r2|
w = 2π× | [r1T2- r2T1] / [T1T2/(r1-r2)] |
This is formula for angular speed of satelite s2 w.r.t. s1.
Hope this was useful...
Answered by
1
Angular speed of satelite s2 w.r.t. s1 when they are closest to each other is given by,
w = |v1-v2| / |r1-r2|
But for planetary motion,
v1 = 2πr1/T1
v2 = 2πr2/T2
w = 2π× |(r1/T1 - r2/T2 ) ÷ (r1-r2)|
w = 2π× |(r1T2 - r2T1)/T1T2| ÷ |r1-r2|
w = 2π× | [r1T2- r2T1] / [T1T2/(r1-r2)] |
This is formula for angular speed of satelite s2 w.r.t. s1.
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