Question

Two seconds later, how far does the stone go from its point of release ? explain?
a. 10.4 m
b. 5.8 m
c. 6.7 m
d. 8.8 m

Answer 1

ANSWER

Given

Last second t=1sec

Distance covered S=24.5m

We know

S=ut+

2

1

at

2

In this case, as the stone is released.

Initial velocity, u=o and

a=g=9.8m/sec

2

S=

2

1

×9.8t

2

=4.9t

2

Distance traveled by stone in the last second is

4.9t

2

−4.9(t−1)

2

=24.5

t

2

−(t−1)

2

=5

(t−t+1)(t+t−1)=5

2t−1=5

t=3sec

Now,

S=ut+

2

1

at

2

S=0+

2

1

×9.8×9

S=44.1m

I hope you are understand my solution

Answer 2

What is the speed of stone