two series resistances are connected to an AC source if there are 7.5 vrms across one resistor and 4.2 vrms across the other, peak source voltage is? pls solve it out
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Answer:
16.546
Explanation:
According to KVL
Algebraic sum of all the voltages in a loop = 0
V = (7.5+4.2)×1.414 = 16.546
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