Math, asked by SharmaShivam, 10 months ago

Two sets A and B are as under:
A = {(a, b) ∈ R × R : |a-5| < 1 and |b-5| < 1} ;
B = {(a, b) ∈ R × R : 4(a-6)² + 9(b-5)² ≤ 36} . Then
(a) neither A ⊂ B nor B ⊂ A
(b) B ⊂ A
(c) A ⊂ B
(d) A ∩ B = Ф (an empty set)

Answers

Answered by Anonymous
1

Answer:

Two sets A and B are as under:

A = {(a, b) ∈ R × R : |a-5| < 1 and |b-5| < 1} ;

B = {(a, b) ∈ R × R : 4(a-6)² + 9(b-5)² ≤ 36} . Then

(a) neither A ⊂ B nor B ⊂ A

(b) B ⊂ A

(c) A ⊂ B

(d) A ∩ B = Ф (an empty set). m

........

Step-by-step explanation:

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Answered by Anonymous
1

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&lt;marquee direction="left"&gt; Hope it helps

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