Two sets of maths and science books containing 1680 1056 books respectively in a library have to be stacked in such a way that all the books are stored subject wise and height of teacher stock is the same assuming that the books are of same thickness determine the total number of stacks
Answers
Answered by
22
Heya Frnd.........☺
No. of books in each stack =
HCF OF 1680, 1056.
Therefore,
By using Euclid's division lemma :-
a = bq + r
=> 1680 = 1056 × 1 + 624
=> 1056 = 624 × 1 + 432
=> 624 = 432 × 1 + 192
=> 432 = 192 × 2 + 48
=> 192 = 48 × 4 + 0
THEREFORE,
HCF (1680,1056) = 48.
SO, THERE ARE ✴48✴ BOOKS IN A STACK.
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No. of books in each stack =
HCF OF 1680, 1056.
Therefore,
By using Euclid's division lemma :-
a = bq + r
=> 1680 = 1056 × 1 + 624
=> 1056 = 624 × 1 + 432
=> 624 = 432 × 1 + 192
=> 432 = 192 × 2 + 48
=> 192 = 48 × 4 + 0
THEREFORE,
HCF (1680,1056) = 48.
SO, THERE ARE ✴48✴ BOOKS IN A STACK.
_______________________
HOPE IT WILL HELP YOU. . . . . . . . . ☺
PLZ MARK MY ANSWER AS BRAINLIEST IF U LIKE IT. . . . . . . . . . . . . . . ⭐
Answered by
6
1680=2×2×2×2×5×3×7
1056=2×2×2×2×2×3×11
HCF=2×2×2×2×3
HCF=48
Hence total number of stacks is 48
1056=2×2×2×2×2×3×11
HCF=2×2×2×2×3
HCF=48
Hence total number of stacks is 48
ragaviragavendrgirly:
Both are correct method...so don't worry...thumbs up
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