Question

two ships are sailing in the sea on either sides of a lighthouse. The angle of elevation of the top of the lighthouse is 200m high ,find the distance between the two ships( 3

=1.732)​

Answer 1

Answer:

273 m

Step-by-step explanation:

Let AB be the lighthouse and C and D be the positions of the ships.

Then, AB=100 m,∠ACB=30

∘

and ∠ADB=45

∘

.

AC

AB

=tan30

∘

=

3

1

⇒AC=AB×

3

=100

3

m.

AD

AB

=tan45

∘

=1⇒AD=AB=100 m.

∴CD=(AC+AD)=(100

3

+100)m

=100(

3

+1)

=(100×2.73)m

=273 m.