Question

Two short bar magnets. A and B of. Dipole moment M1 and M2 respectively are arranged as shown in figure the magnitude of torque on the bar magnet A due to the bar magnet B is
I) u/4π 3M1M2/r^3
II)u/4π6 M1M2/r^4
III)u/2πM1M2/r^3
Iv) zero

Answer 1

Answer:

Torque on bar magnet M1 due to another bar magnet M2 is ZERO

Explanation:

As we know that magnitude of torque on bar magnet is given by the formula

$\tau = \vec M \times \vec B$

so here we need to find the magnetic field due to bar magnet 2 on the position of bar magnet 1

so we know that the formula of axial magnetic field is given as

$B = \frac{2\mu_o M_2}{4\pi r^3}$

the direction of magnetic field here is along the direction of the magnetic moment of the bar magnet

so we have

$\tau = \vec M_1 \times \vec B$

$\tau = (\vec M_1)(\vec B)sin0$

$\tau = 0$

So Torque on the bar magnet will be Zero

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Topic : Torque on bar magnet

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