Physics, asked by sujana1234, 1 year ago

Two short magnets apply a force F on each other. If the separation between them is halved then new force
between them is approximately
(1) 8F
(3) 16 F​

Answers

Answered by anand5875
1

i think so tha answer is 8 F

Answered by gadakhsanket
3

Hello Dear,

◆ Answer -

F' = 4 F

◆ Explaination -

According to Coulomb's law -

F = (μ/4π) m1.m2 / r^2

When separation between magnets is halved, i.e. r' = r/2

F' = (μ/4π) m1.m2 / r'^2

F' = (μ/4π) m1.m2 / (r/2)^2

F' = 4 × (μ/4π) m1.m2 / r^2

F' = 4 F

Therefore, force of magnetism between two magnets will be quadrupled on halving separation.

Thanks dear...

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