Two short magnets apply a force F on each other. If the separation between them is halved then new force
between them is approximately
(1) 8F
(3) 16 F
Answers
Answered by
1
i think so tha answer is 8 F
Answered by
3
Hello Dear,
◆ Answer -
F' = 4 F
◆ Explaination -
According to Coulomb's law -
F = (μ/4π) m1.m2 / r^2
When separation between magnets is halved, i.e. r' = r/2
F' = (μ/4π) m1.m2 / r'^2
F' = (μ/4π) m1.m2 / (r/2)^2
F' = 4 × (μ/4π) m1.m2 / r^2
F' = 4 F
Therefore, force of magnetism between two magnets will be quadrupled on halving separation.
Thanks dear...
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