two shower each of mass 1000kg with center distance 1m a apart find the gravitational force with which attract each other.
f= G m1 m2 / r2
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Answered by
1
F = G m1 m2/ r2
F = 9.8 x 1000 x1000 /1^2
F = 9800000
F = 9.8 x 1000 x1000 /1^2
F = 9800000
Answered by
9
Gravitational force is given by :-
F=Gm1m2/r^2
Given data :-
m1 =m2=1000kg
r=1m
And we know that G is gravitational constant ,its value is 6.67×10^_11Nm^2/kg^2
Now F=Gm1m2/r^2
F = 6.67×10^_11 × 1000 ×1000/1^2 (1000×1000=10^6 , and 1^2 = 1 )
F = 6.67×10^_11 × 10^6
F = 6.67 ×10^_11+6
F = 6.67×10^_5 N
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F=Gm1m2/r^2
Given data :-
m1 =m2=1000kg
r=1m
And we know that G is gravitational constant ,its value is 6.67×10^_11Nm^2/kg^2
Now F=Gm1m2/r^2
F = 6.67×10^_11 × 1000 ×1000/1^2 (1000×1000=10^6 , and 1^2 = 1 )
F = 6.67×10^_11 × 10^6
F = 6.67 ×10^_11+6
F = 6.67×10^_5 N
_________________________
INSHALLAH IT WILL HELP U
HAVE A NICE DAY ☺☺☺☺
Anonymous:
6 ? do u mean that 10^6 ?
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