Math, asked by arshoobaluch, 11 months ago

two shower each of mass 1000kg with center distance 1m a apart find the gravitational force with which attract each other.

f= G m1 m2 / r2

Answers

Answered by PrinceKhandelwal
1
F = G m1 m2/ r2
F = 9.8 x 1000 x1000 /1^2
F = 9800000
Answered by Anonymous
9
Gravitational force is given by :-

F=Gm1m2/r^2

Given data :-

m1 =m2=1000kg

r=1m

And we know that G is gravitational constant ,its value is 6.67×10^_11Nm^2/kg^2

Now F=Gm1m2/r^2

F = 6.67×10^_11 × 1000 ×1000/1^2 (1000×1000=10^6 , and 1^2 = 1 )

F = 6.67×10^_11 × 10^6

F = 6.67 ×10^_11+6

F = 6.67×10^_5 N

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Anonymous: 6 ? do u mean that 10^6 ?
arshoobaluch: yess
arshoobaluch: your whatsApp number please ??
Anonymous: 1000 means 10 power 3 , and there are two 1000 that is m1 and m2 so 10^3+3=10^6
Anonymous: got it ?
arshoobaluch: thank you so much
arshoobaluch: your number please
Anonymous: my pleasure
arshoobaluch: i want your number
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