Question

. Two sides of a parallelogram are 10 cm and 12 cm. If the altitude corresponding to the
side of length 12 cm is 15 cm, find the altitude corresponding to the other side.​

Answer 1

the two sides of a parallelogram are 10 and 12 cm these are the bases

area of parallelogram= base ×height

area = base ×height
= 12×15=180 sq. cm
so area of parallelogram = b×h
180 sq. cm = 10 ×h
height= 180/10 cm = 18 cm


height of one side = 15 cm

Answer 2

The altitude corresponding to the other side 10 cm is 18 cm.

Step-by-step explanation:

Since we have given that

Length of sides = 10 cm and 12 cm.

Altitude corresponding to the side of length 12 cm is 15 cm.

Area of parallelogram is given by

$Area=base\times height\\\\Area=12\times 15\\\\Area=180\ cm^2$

So, the altitude corresponding to the side of length 10 cm is given by

$180=10\times h\\\\\dfrac{180}{10}=h\\\\18=h$

Hence, the altitude corresponding to the other side 10 cm is 18 cm.

# learn more:

In the figure, in triangle ABC, BC=16cm, AC=12cm, AB=10cm and altitude AD=6cm.Find (a)BE (b)altitude on side AB.​

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