Two sides of a square are (x + 3) cm and (2x - 2) cm. The area of the square is
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the sides are (x+3) and (2x-2)
as per square,
(x+3)=(2x-2)
x-2x=-2-3
-x=-5
x=5
substitute x value in the side (x+3)
=(x+3)
=5+3
=8
a=8
area of square=a^2
=8^2
=64sq. cm.
hope it hlps u
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as per square,
(x+3)=(2x-2)
x-2x=-2-3
-x=-5
x=5
substitute x value in the side (x+3)
=(x+3)
=5+3
=8
a=8
area of square=a^2
=8^2
=64sq. cm.
hope it hlps u
follow me
Anonymous:
tq
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