Question

Two sides of a triangle are 8cm $ 11cm and its peremeter is 32cm. find area of triangle

Answer 1

sides are 8, 11 and 13 so by herons formula
we get
area=
$\sqrt{16 \times 8 \times 3 \times 5 }$
=
$8 \sqrt{3}$

Answer 2

Heya!
--------

========================================================

♦Given that =>
==============


✔Two sides of a Triangle are 8 cm and 11 cm .

Perimeter = Sum of All sides

=> X + 8 + 11 = 32

=> X + 19 = 32

=> X = 13 cm .



♦Area by Heron's Formula =>
=======================


➡Semi Perimeter s = 13+8+11 / 2

=> S = 32/2

=> S = 16...............(1)


♦Heron's Formula =>


$= > \sqrt{s(s - a)(s - b)(s - c)} \\ \\ = > \sqrt{16(16 - 8)(16 - 11)(16 - 13) } \\ \\ = > \sqrt{16 \times 8 \times 3 \times 5} \\ \\ = > \sqrt{1920 } \\ \\ = > > 8 \sqrt{30} cm {}^{2}$

=>> 43.81 cm² approx.


============================================================