two sides of the trapezium are in the ratio 7:1 distance between them is 17 cm .if the area is 306cm^.find the length ofthe parallel sides
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area of trapezium= H/2*(a+b)
=17/2*(7x+1x)= 306
=17*4x=306
=4x=18
X=9/2
one side=63/2
other side= 9/2
=17/2*(7x+1x)= 306
=17*4x=306
=4x=18
X=9/2
one side=63/2
other side= 9/2
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Given
Ratio of two parallel sides =a:b=7:1
a=7x cm
b=1lcm
Distance between them=h=17cm
Area of the trapezium=306 cm^2
(7x+x)*17/2=306
8x*17/2x=306
x=(306*2)/(8*17)
x=(2*3**17*3*2)/(2*2*2*17)
x=9/2
Therefore
a=7x=7*9/2=63/2=31.5cm
b=x=9/2=4.5cm
Ratio of two parallel sides =a:b=7:1
a=7x cm
b=1lcm
Distance between them=h=17cm
Area of the trapezium=306 cm^2
(7x+x)*17/2=306
8x*17/2x=306
x=(306*2)/(8*17)
x=(2*3**17*3*2)/(2*2*2*17)
x=9/2
Therefore
a=7x=7*9/2=63/2=31.5cm
b=x=9/2=4.5cm
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