Two similar cells, whether joined in series or in parallel, have the same current through an external resistance of 2 ohm . The internal resistance of each cell is
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Answer:
Let ε, r be the emf and internal resistance of each cell. External R=1Ω.
When the two cells are connected in series
Total emf of cells =ε+ε=2ε
Total resistance of circuit =R+r+r=1+2r
Currnet in the circuit, I1=2ε1+2r
When the two cells are connseted in parallel
Effective emf of two cells = emf of single cell=ε
Total internal resistance of two cells
r×rr+r=r2
Total resistance of the circuit =R+r/2=1+r/2.
Current in the circuit, I2=ε1+r/2
As per question, I1=I2
So, 2ε1+2r=ε1+r/2=2ε2+r
or 1+2r=2+rorr=1Ω
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Explanation:
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