Question

Two similar circular loops of radius R are lying concentrically with their planes at right angles to each other. The currents flowing in them are I and I root 3.magnetic field at the centre of coil is explain with a diagram

Answer 1

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B1 = mu.nod I / 2R

B2 = mu.nod root3 I/ 2R

Net magnetic field = Vector sum of B1 and B2

B° = √(B1^2 + B2^2 + 2B1B2cos90°)

B° = (mu.nod I /2R) × 2

B° = mu.nod.I /R