two similar triangles abc and pcb are made on opposite sides of the same base prove ab=pb
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since ΔABC ~ΔPCB
angle 1= angle 2
angle 3= angle4
but they are alternate angles
therefore,AC\\BP and AB\\PC
hence ACPB is parallelogram where both pair of opposite angles are parallel
angle 1= angle 2
angle 3= angle4
but they are alternate angles
therefore,AC\\BP and AB\\PC
hence ACPB is parallelogram where both pair of opposite angles are parallel
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swathika23:
but you should prove that AB=PB
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