Question

Two simple pendulums have their lengths as 1.44
and 1.69 m respectively. They start in phase fror
the mean position simultaneously. After how man
oscillations of the longer pendulum they will be
phase again?​

Answer 1

Answer:

Two simple pendulums have their lengths as 1.44

and 1.69 m respectively. They start in phase fror

the mean position simultaneously. After how man

oscillations of the longer pendulum they will be

phase again

o_O.

Answer 2

Number of oscillations of larger pendulum after which they will be in phase again = 120

• Oscillation depend on time period.

• Time period is directly proportional to √l

• Ratio of time period between the two pendulums = √1.69/√1.44

                                                                                         = 1.3/1.2

• The LCM of this periods will give the common oscillation. Make LCM into a non decimal number. You will get 120 oscillations for larger pendulum and 130 for smaller one.