Two sirens produce sound of intensities 5 x 10-9 W/m2
and 9 x 10-6 W/m² respectively. By how many decibels is
one sound louder over other?
Answers
Given : Two sirens produce sound of intensities 5 x 10^-9 W/m2 and 9 x 10^-6 W/m2 respectively
To Find : By how many decibels is one sound louder over
other?
a) 3 dB
b) 13 dB
c) 25.7 dB
d) 32.5 dB
Explanation:
The loudness, L, measured in decibels (Db), of a sound intensity, I, measured in watts per square meter,
L = 10 log (I / I₀)
I₀ = 10⁻¹²
sirens produce sound of intensities 5 x 10⁻⁹ W/m²
L = 10 log (5 x 10⁻⁹/ 10⁻¹² )
=> L = 10 log (5000)
=> L = 10 log5 + 10 log 1000
=> L = 10log5 + 30
=> L = 10log5 + 30
=> L = 6.99 + 30
=> L = 36.99
=> L = 37
sirens produce sound of intensities 9 x 10⁻⁶ W/m²
L = 10 log ( 9 x 10⁻⁶/ 10⁻¹² )
=> L = 10 log (9 x 10⁶)
=> L = 10 log9 + 10 * 6
=> L = 9.5 + 60
=> L = 69.5
69.5 - 37
= 32.5 dB
By 32.5 decibels is one sound louder over other
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Answer:
Given : Two sirens produce sound of intensities 5 x 10^-9 W/m2 and 9 x 10^-6 W/m2 respectively
To Find : By how many decibels is one sound louder over
other?
a) 3 dB
b) 13 dB
c) 25.7 dB
d) 32.5 dB
Explanation:
The loudness, L, measured in decibels (Db), of a sound intensity, I, measured in watts per square meter,
L = 10 log (I / I₀)
I₀ = 10⁻¹²
sirens produce sound of intensities 5 x 10⁻⁹ W/m²
L = 10 log (5 x 10⁻⁹/ 10⁻¹² )
=> L = 10 log (5000)
=> L = 10 log5 + 10 log 1000
=> L = 10log5 + 30
=> L = 10log5 + 30
=> L = 6.99 + 30
=> L = 36.99
=> L = 37
sirens produce sound of intensities 9 x 10⁻⁶ W/m²
L = 10 log ( 9 x 10⁻⁶/ 10⁻¹² )
=> L = 10 log (9 x 10⁶)
=> L = 10 log9 + 10 * 6
=> L = 9.5 + 60
=> L = 69.5
69.5 - 37
= 32.5 dB
By 32.5 decibels is one sound louder over other
Learn More:
if the loudness of a sound is reduced to 36% then the amplitude gets ...
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Music is been played in two opposite galleries with certain group of ...
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The SI unit of luminous intensity is ______.A. watt B. luxC. lumen D ...
brainly.in/question/4619034