Two skaters on in-line skates, A and B, are initially at rest. They push apart and start moving in opposite directions. If A's speed just after they push apart is 3.0 m/s and mass of A is 75% of B's mass, how fast is B moving at that time?
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Answer:
Given,
Initial velocity, u
1
=0andu
2
=0
Mass,m
1
=60kgandm
2
=40kg
Final Velocity, v
1
=2ms
−1
From conservation of momentum
Final momentum = initial momentum
m
1
v
1
+m
2
v
2
=m
1
u
1
+m
2
u
2
60×2+40v
2
=0
v
2
=−3ms
−1
Hence, velocity of second skater is −3ms
−1
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