Question

Two small neutral conducting spheres are taken and their centres are seperated by a distance 2a .If n electrons are removed from one of them and deposited on the other, what is the magnitude of electric field intensity due to the system at a point on the line joining the center's of the spheres and at a distance d from the midpoint of the line joining the two spheres ?​

Answer 1

Explanation:

Charge of each electron e=1.6×10

−19

C

Number of electrons removed from the sphere n=4×10

10

Thus total charged removed from the sphere q=ne

∴ q=4×10

10

×1.6×10

−19

=6.4×10

−9

C

Distance of point from the center of sphere r=20cm=0.2m

Thus electric field at that point E=

r

2

kq

where k=

4πϵ

o

1

=9×10

9

⟹ E=

(0.2)

2

9×10

9

×6.4×10

−9

=1440NC

−1