two small objects are rubbed against each other and kept at distance 1m away in vaccum .they attract each other with a force of 10 N find the no of electrons transfered from one to another
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since force= kq1q2/r'2
since q1= -q2 (the fundamental law of nature-conservation of charnges)
so force =kq'2/r'2=10N
since r=1m.
kq'2=10
since k=8.85*10'(8)
then q'2=10/k
put the value of k the take the root of the no. you got that will give you q.
and since 1 electron has charge= 1.62*10'(-19). so the no of electrons will be =q/(1.62*10'(-19))
that's it.
if you didn't get anywhere ask.
note- appstrope has been used to represent the power of a no.
since q1= -q2 (the fundamental law of nature-conservation of charnges)
so force =kq'2/r'2=10N
since r=1m.
kq'2=10
since k=8.85*10'(8)
then q'2=10/k
put the value of k the take the root of the no. you got that will give you q.
and since 1 electron has charge= 1.62*10'(-19). so the no of electrons will be =q/(1.62*10'(-19))
that's it.
if you didn't get anywhere ask.
note- appstrope has been used to represent the power of a no.
mohit143776:
sorry but i didn't get the answer
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