Question

if cot theta =2, find the value of cot^2 theta + cosec^2 theta

Answer 1

Step-by-step explanation:

${ \cot }^{2} \alpha + { \cosec }^{2} \alpha \\ \\ = { \cot}^{2} \alpha + { \cot }^{2} \alpha + 1 \\ = 2 { \cot }^{2} \alpha + 1 \\ = 2 ({2})^{2} + 1 \\ = 8 + 1 = 9$