Two smaller circles touch a large circle internally and pass through the center o of the larger circle. if the diameter of the bigger circle is 28 cm, then what is the area of the bigger circle which is not enclosed by the two smaller circles (in cm2)?
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The diameter of the bigger circle = 28cm
The radius of the larger circle = 28/2 = 14 cm
The diameters of the smaller circles = 28/2 = 14 cm
The radius of the smaller circle = 14/2 = 7cm
The area of the larger circle = 22/7 x 14² = 616 cm²
Areas of the two smaller circles = 2 x 22/7 x 7² = 308cm²
The area of the bigger circle which is not enclosed by the two smaller circles
= 616 - 308
= 308 cm²
The radius of the larger circle = 28/2 = 14 cm
The diameters of the smaller circles = 28/2 = 14 cm
The radius of the smaller circle = 14/2 = 7cm
The area of the larger circle = 22/7 x 14² = 616 cm²
Areas of the two smaller circles = 2 x 22/7 x 7² = 308cm²
The area of the bigger circle which is not enclosed by the two smaller circles
= 616 - 308
= 308 cm²
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Answer:
Step-by-step explanation:
If the brothers are x
The number of sons = (x -1)x = x² - x
The total number = x + x² - x
= x²
A perfect square that lies between 50 and 70 is 64
So Lucia (The grandmother) is 64 years old
NOTE:
x² = 64
x = 8
There are 8 brothers each with 7 sons
One of the brothers will say that he has 7 brothers and 7 sons
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