Two solenoids of same cross-sectional area have their
lengths and number of turns in ratio of 1 : 2. The ratio of
self-inductance of two solenoids is
(a) 1 : 1 (b) 1 : 2 (c) 2 : 1 (d) 1 : 4
Answers
Answered by
1
Answer:
self-inductance is directly proportional to the square of its number of turns
L
2
L
1
= (
N
2
N
1
)
2
L
1
L
2
=
4
1
Answered by
0
Answer:
self-inductance is directly proportional to the square of its number of turns
Explanation:
L1/L2 = N1 square . I2 / I1 . N2 square
= 1 . 2/ 2.1 = 1/1
so the answer is L1:L2 = 1:1
Similar questions