Two solid spherical planets of equal radii R having masses 4 M and 9 M their centre are separated by a distance 6 R. A projectile of mass m is sent from the planet of mass 4 M towards the havier planet. what is the distance r of the point from the lighter planet where the gravitational force on the projectile is zero?
Answers
Radii of solid spherical planets = R1 = 4M
Radii of solid spherical planets = R2 = 9M
The gravitational force will be zero where the field is zero.
The direction of the field due to both the planets will be opposite and cancel each other some where between the planets.
Let at a distance of x from the planet of mass 4M where the field is zero.
Therefore,
G4M/ X² = G9M/ ( 6R-X)²
X = √G4M6R/ √G4M + √G9M
= 12/5R distance from the planet of mass 4M the force will be zero.
Radii of solid spherical planets = R1 = 4M
Radii of solid spherical planets = R2 = 9M
The gravitational force will be zero where the field is zero.
The direction of the field due to both the planets will be opposite and cancel each other some where between the planets.
Let at a distance of x from the planet of mass 4M where the field is zero.
Therefore,
G4M/ X² = G9M/ ( 6R-X)²
X = √G4M6R/ √G4M + √G9M
= 12/5R distance from the planet of mass 4M the force will be zero.