two solids of right cylinder kal Shaikh R 49 CM in 35 cm height and their base diameters are 16 cm 14 cm respectively both are melted and moulded into a single cylinder 56 cm height find its base diameter
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formula for volume of cylinder is ( pi r×r h)
volume of 1st cylinder is
pi*64*49=pi*3136
volume of 2nd cylinder is
pi*49*35=pi*1715
and the height of single cylinder is 56cm
therfore
V of single cylinder =v of 1st cylinder + v of 2nd cylinder
pi*r^2*56=pi*3136+pi*1715
pi*r^2=pi*4851÷56
r^2=86.625
r=9.30
volume of 1st cylinder is
pi*64*49=pi*3136
volume of 2nd cylinder is
pi*49*35=pi*1715
and the height of single cylinder is 56cm
therfore
V of single cylinder =v of 1st cylinder + v of 2nd cylinder
pi*r^2*56=pi*3136+pi*1715
pi*r^2=pi*4851÷56
r^2=86.625
r=9.30
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