Question

two sound waves having a phase difference of 60 degree have path difference of

Answer 1

Given that two sound waves have the same frequency f, and wavelength λ.

The have a phase difference of 60°.

For a phase difference of 360° or 2π rad, the path difference is equal to the wavelength λ.

So for the phase difference of 60°, the path difference will be 
  = λ * 60°/360° = λ / 6

= one sixth of the wavelength.

Answer 2

it's decrease to 1/6 of its actual wavelength