Question

Two sound waves having a phase difference of 60degree have path difference of

Answer 1

question is incomplete , for finding path difference wavelength is required ,
e.g ∆@ = (2π/lemda)∆x
where ∆@ is phase difference
∆x is the path difference

now,
∆@ =60° =π/3

so, ∆x =(lemda/2π) x π/3
=lemda/6