Physics, asked by itwinasilele710, 9 months ago

Two sound waves X and Y are compared.X has the greater frequency.Y has the greater amplitude.How do the loudness and pitch of sound wave Y compare to those of X?

Answers

Answered by abhisgh9934
0

Answer: Y is greater than X

Explanation:

Answered by stalwartajk
0

Answer:

X has a higher pitch than Y.

Y has a higher loudness than X.

Explanation:

Given that,

There are two sound waves, and both are compared in terms of frequency and amplitude.

Sound wave X has a greater frequency.

Sound wave Y has greater amplitude.

As we know,

The pitch of the sound wave is directly proportional to its frequency.

Pitch ∝ Frequency

So, as sound wave X has a higher frequency, it has a higher pitch.

∴ The pitch of X > pitch of Y

We know that,

The loudness of the sound wave is directly proportional to its amplitude

Loudness ∝ Amplitude

So, as sound wave Y has a higher amplitude, it has a higher loudness.

∴ Loudness of Y > Loudness of X

To know more about the pitch, visit the below link:

https://brainly.in/question/6269123

To know more about the loudness, visit the below link:

https://brainly.in/question/48257059

#SPJ3

Similar questions