Question

Two spherical bodies attract each other with the gravitational force of 4.0 N. What will be the force if the distance between them is doubled?

* 1.0 N * 2.0 N

* 4.0 N * 16.0 N​

Answer 1

Applied force F=4N

The mass of the body to which the force is applied is m=2kg

By Newton's law acceleration produced a=Fm=42=2ms−2

The initial velocity of the body u=0

Tthe distance covered in first phase i.e. t=4 sec after the force starts acting will be

S1=u×t+12a×t2=0×4+12×2×42=16m

The forces ceases to act after 4 sec and the body moves with uniform velocity attained after 4sec.

The velocity attained v=u+a×t=0+2×4=8ms−1

So the distance covered in 2nd phase i.e. in 6sec will be

S2=v×6=8×6=48m

So total distance covered in 10sec will be

Stotal=S1+S2=16+48=64m