Two springs of spring constant 1500N/m and 3000N/m respectively are stretched with same force. they will have potential energies in the ratio
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Potential energy = -F² / (2K)
For same force
Potential energy ∝ 1/K
Ratio of potential energies = K₂ : K₁
= 3000 N/m : 1500 N/m
= 2 : 1
Ratio of potential energy stored is 2 : 1
For same force
Potential energy ∝ 1/K
Ratio of potential energies = K₂ : K₁
= 3000 N/m : 1500 N/m
= 2 : 1
Ratio of potential energy stored is 2 : 1
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