Question

Two squares of sides 19cm are placed side by side without any gap. Find the (1) perimeter (2) area of the rectangle formed

Answer 1

Your answer is in the attachment

Answer 2

$Given \: sides \: of \: two \: squares (a) = 19\:cm$

/* According to the problem given */

If two cubes placed side by side without any gap then new shape formed at base is a rectangle*/

$Now, Length \: of \:the \: rectangle = 2a \\= 2\times 19\:cm \\= 38\:cm$

$Breadth \: of \:the \: rectangle = a = 19\:cm$

$1 ) Perimeter \:of \:the \: rectangle \\= 2(l+b) \\= 2( 38+19)\\= 2\times 57 \\= 114 \:cm$

$2 )Area \:of \:the \: rectangle \\= l \times b \\= 38\:cm \times 19 \:cm \\= 722 \:cm^{2}$

Therefore.,

$\red{Perimeter \:of \:the \: rectangle}\green {=114 \:cm}$

$\red{Area \:of \:the \: rectangle}\green {=722 \:cm^{2}}$

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